11-(1/t)=10/t^2

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Solution for 11-(1/t)=10/t^2 equation:


D( t )

t^2 = 0

t = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

11-(1/t) = 10/(t^2) // - 10/(t^2)

11-(1/t)-(10/(t^2)) = 0

11-t^-1-10*t^-2 = 0

t_1 = t^-1

11-10*t_1^2-1*t_1^1 = 0

11-10*t_1^2-t_1 = 0

DELTA = (-1)^2-(-10*4*11)

DELTA = 441

DELTA > 0

t_1 = (441^(1/2)+1)/(-10*2) or t_1 = (1-441^(1/2))/(-10*2)

t_1 = -11/10 or t_1 = 1

t_1 = -11/10

t^-1+11/10 = 0

1*t^-1 = -11/10 // : 1

t^-1 = -11/10

-1 < 0

1/(t^1) = -11/10 // * t^1

1 = -11/10*t^1 // : -11/10

-10/11 = t^1

t = -10/11

t_1 = 1

t^-1-1 = 0

1*t^-1 = 1 // : 1

t^-1 = 1

-1 < 0

1/(t^1) = 1 // * t^1

1 = 1*t^1 // : 1

1 = t^1

t = 1

t in { -10/11, 1 }

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